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Kinetic theory and temperature in gases

  1. Jun 10, 2008 #1
    1. The problem statement, all variables and given/known data
    Temperature of a gas (in kelvin) is proportional to the average kinetic temperature of its particles.

    Question: The temperature of 55k (277C) to 1100k(827C). At 277C the mean kinetic energy of the gas is 1.14x10^20. What is it at 827C?

    2. Relevant equations
    kinetic energy= ½ x mass x (velocity)²

    3. The attempt at a solution

    55k to 1100k is x20. 1.14x10^20 x20=2.28x10^21.

    Just wanna check this is correct as I have an exam tormorrow.
    Last edited: Jun 10, 2008
  2. jcsd
  3. Jun 10, 2008 #2
    I'm fairly out of it because I'm pretty tired, but seems alright to me.
  4. Jun 10, 2008 #3
    Alright, cheers mate.
  5. Jun 10, 2008 #4


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    How is 55K = 277C??
  6. Jun 10, 2008 #5
    5k maybe? I just noticed that now...
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