Kinetic theory and temperature in gases

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Homework Help Overview

The discussion revolves around the relationship between temperature and the average kinetic energy of gas particles, specifically examining the kinetic energy at two different temperatures in Celsius and Kelvin.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the mean kinetic energy of gas particles at a higher temperature based on a proportional relationship. Some participants question the conversion between Kelvin and Celsius, particularly the initial temperature values provided.

Discussion Status

The discussion is ongoing with participants providing feedback on the original poster's calculations. There is some uncertainty regarding the temperature conversions, and participants are exploring the implications of these conversions on the calculations.

Contextual Notes

There is a noted confusion regarding the conversion from Kelvin to Celsius, with one participant suggesting a possible error in the initial temperature stated by the original poster.

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Homework Statement


Temperature of a gas (in kelvin) is proportional to the average kinetic temperature of its particles.

Question: The temperature of 55k (277C) to 1100k(827C). At 277C the mean kinetic energy of the gas is 1.14x10^20. What is it at 827C?

Homework Equations


kinetic energy= ½ x mass x (velocity)²

The Attempt at a Solution



55k to 1100k is x20. 1.14x10^20 x20=2.28x10^21.

Just want to check this is correct as I have an exam tormorrow.
 
Last edited:
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I'm fairly out of it because I'm pretty tired, but seems alright to me.
 
lukas86 said:
I'm fairly out of it because I'm pretty tired, but seems alright to me.

Alright, cheers mate.
 
How is 55K = 277C??
 
5k maybe? I just noticed that now...
 

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