• Support PF! Buy your school textbooks, materials and every day products Here!

Kinetics, force and acceleration

  • Thread starter red123
  • Start date
  • #1
22
0

Homework Statement



The crate has a mass of 80 kg and is being towed by a chain which is always directed at 20º from the horizontal has shown. Determine the crate's acceleration in t = 2 s if the coefficient of static friction is μs = 0.4, the coefficient of kinetic friction is μk = 0.3, and the towing force is P = (90t2) N, where t is in seconds.

rau7pi.jpg


Homework Equations



ΣF = ma

The Attempt at a Solution



ΣFx = max
Pcos(20º) - μkmg = ma
84.57t2 - 235.44 = (80 kg)a

solving for a when t = 2
a = 1.29 m/s2

The answer at the back of my book is a = 1.75 m/s2. I think I'm supposed to consider that static friction force is greater than kinetic friction force, but I can't figure out how to do that.
 

Answers and Replies

  • #2
Doc Al
Mentor
44,882
1,129
ΣFx = max
Pcos(20º) - μkmg = ma
The force of friction is μN, but N does not simply equal mg. Solve for N, taking into consideration that the applied force is at an angle.
 
  • #3
22
0
The force of friction is μN, but N does not simply equal mg. Solve for N, taking into consideration that the applied force is at an angle.
Then N = mg*cos(20°)?
But that gives a = 1.46 m/s2, not a = 1.75 m/s2.
 
  • #4
Doc Al
Mentor
44,882
1,129
Then N = mg*cos(20°)?
How did you come to that conclusion?

To solve for N, add up the vertical components of all forces acting on the body. (N is one of those forces.) The sum must be zero, since the body is not accelerating vertically.
 
  • #5
22
0
Thank you, Doc Al.
 

Related Threads for: Kinetics, force and acceleration

Replies
1
Views
41K
Replies
20
Views
958
  • Last Post
Replies
13
Views
1K
Top