Kirchhoff's Current Law problem

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jgv115
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Homework Statement


Circuit schematic with resistors Ra = 6 kΩ, Rb = 9 kΩ, Rc = 8 kΩ, Rd = 3 kΩ, current sources Is1 = 10 mA and Is2 = 9 mA, and labelled current IA flowing from the bottom node of Rc.



The Attempt at a Solution



Currents entering the top node...

[itex]\frac{V}{6000} - 0.01 - \frac{V}{9000} - \frac{V}{8000} + 0.009 - \frac{V}{3000} = 0[/itex]

Solve for V I get -2.48

The current Ia is the addition of the current going out of Rd add Is2

so... [itex]I = \frac{2.48}{3000} =0.000823[/itex] Therefore.. [itex]I_{A} = 0.000823 - 0.009= -0.008172[/itex] This is wrong... the answer is -9.45mA and I get -8.17mA

Anyone care to help me out!
 
Check the sign on the first term of your KCL equation...
 
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