Kirchoffs current law. Someone check to make sure its correct?

[Agnostic]

In the picture.

 

[data1217]

Due to the series configuration, Ic and Id are equal in magnitude but opposite in direction.
if Ia = 3A, Ic = 1A, then Id = -1A
Ia + Ic - Id - Ib = 0
3A + 1A - 1A - Ib = 0
as a result, Ia=Ib = 3A

 

[Valhalla]

Due to the series configuration, Ic and Id are equal in magnitude but opposite in direction.
if Ia = 3A, Ic = 1A, then Id = -1A
Ia + Ic - Id - Ib = 0
3A + 1A - 1A - Ib = 0
as a result, Ia=Ib = 3A

I agree with the Ic Id sign. However, Using the Node with Ia and Ic entering and Ib leaving and using KCL. I get Ia+Ic-Ib=0 therefore Ia+Ic=Ib or 3A + 1A =4A

 

[data1217]

I agree with the Ic Id sign. However, Using the Node with Ia and Ic entering and Ib leaving and using KCL. I get Ia+Ic-Ib=0 therefore Ia+Ic=Ib or 3A + 1A =4A

You are right.
for the node with Ib and Id entering, Ia leaving
-Ia + Ib + Id = 0
-3 + Ib + -1 = 0
Ib =4A