Finding the Unknown Resistance Value

Click For Summary

Homework Help Overview

The discussion revolves around finding the unknown resistance value in a circuit involving resistors R1, R2, R3, and an unknown resistor R, with a given voltage. The problem context includes the behavior of current through R1 under different switch configurations.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the addition of resistor values and the implications of current remaining constant regardless of switch positions. Questions arise about the application of Kirchhoff's rules and Ohm's Law, as well as the method for calculating current through R1.

Discussion Status

The conversation is ongoing, with participants exploring different interpretations of the circuit setup and the calculations involved. Some guidance has been offered regarding the use of Ohm's Law instead of Kirchhoff's rules, and there is an emphasis on clarifying the circuit layout for better understanding.

Contextual Notes

Participants express confusion regarding the role of switches in the circuit and the calculation of current through R1, indicating potential gaps in understanding the circuit's behavior under different configurations.

Lamp Guy
Messages
8
Reaction score
0

Homework Statement


The current going through the resistor R1 in the figure does not change whether the two switches S1 and S2 are both open or both closed. The resistances are R1 = 70.00 Ω, R2 = 50.00 Ω, and R3 = 62.00 Ω. The voltage is V = 15 V. With this information, what is the value of the unknown resistance R? Recall that a conducting wire can be treated as a resistor of 0 Ω, and points on a wire between resistors are at the same potential. Hint:
Kirchoff's rules are useful here.

The image is found here: http://www.chegg.com/homework-help/questions-and-answers/current-going-resistor-r1-figure-change-whether-two-switches-s1-s2-open-closed-resistances-q4890516

Homework Equations


R(for series)=R1+R2+R3
R(for parallel)=R1*R2/(R1+R2)

The Attempt at a Solution


I tried to add up all three resistors originally and got 182 ohms total, then made that equal to 50 + (70R)/(70+R) but it's not working. Not quite sure how to apply Kirchoff's rules here so any help would be appreciated.
 
Physics news on Phys.org
Can you explain why you added up some resistor values? That will indicate whether you see the problem clearly.

You don't need Kirchoff's Laws, specifically. Ohm's Law will suffice. :)
 
I added them up because it said that the current is the same no matter what, so that's how I found the overall current.
 
Lamp Guy said:
I added them up because it said that the current is the same no matter what, so that's how I found the overall current.
Okay. That's with the switches in the positions shown? What numbers did you add? Did you do the addition in your head, or did you use a calculator?
 
i added 70, 50 and 62 to get 183.
 
182*
 
Lamp Guy said:
182*
Okay. (I was using the values on the figure.)

So that will allow you to calculate the current in R1? What value is it?

Next, how to determine R1's current with the switches closed?
 
Lamp Guy said:
... then made that equal to 50 + (70R)/(70+R) but it's not working. Not quite sure how to apply Kirchoff's rules here so any help would be appreciated.
What you are doing here is setting the battery currents equal, because you are equating the loop resistances. BUT the current through R1 is only a fraction of the battery current, with the switches closed.

So you have yet to find an expression for the current through R1 with switches closed. It would be a good idea to redraw the circuit as simply as possible, so you see clearly what is needed.
 
How do I find out what the current through R1 is? I thought that since it was parallel with the missing R, it would be 70R/(70+R). I've never worked with switches so I'm pretty confused by them.
 
  • #10
Lamp Guy said:
How do I find out what the current through R1 is? I thought that since it was parallel with the missing R, it would be 70R/(70+R).
70R/(70+R) is the equivalent resistance of the parallel pair. Once you know the current through that pair then you need to sort out how much of it goes through each.

I've never worked with switches so I'm pretty confused by them.
That's why I suggested you redraw the circuit with the bare minimum necessary, for clarity. Draw it with no switches, etc. :cool:
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 23 ·
Replies
23
Views
3K
Replies
9
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K