Knights' Collision: Solving a 1D Kinematics Problem for Homework

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SUMMARY

The problem involves two knights, Sir George and Sir Alfred, starting from rest 62 meters apart and accelerating towards each other with accelerations of 0.21 m/s² and 0.26 m/s², respectively. To determine the collision point, the equations of motion for both knights must be established, leading to the equations X1 = (1/2)(0.21 m/s²)t² and X2 = (1/2)(0.26 m/s²)t². By setting the sum of their distances equal to 62 meters and utilizing the ratio of their accelerations, X1/X2 = a1/a2, the collision distance from Sir George's starting point can be calculated.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Familiarity with acceleration and its impact on motion
  • Ability to solve algebraic equations
  • Knowledge of the concept of relative motion
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  • Study the derivation of kinematic equations for uniformly accelerated motion
  • Learn how to apply ratios in physics problems involving multiple objects
  • Explore the concept of relative velocity in one-dimensional motion
  • Practice solving problems involving two objects moving towards each other with different accelerations
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Neil6790
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Homework Statement


In a historical movie, two knights on horseback start from rest 62 m apart and ride directly toward each other to do battle. Sir George's acceleration has a magnitude of 0.21 m/s2, while Sir Alfred's has a magnitude of 0.26 m/s2. How far from Sir George's starting point do the knights collide?

Homework Equations





The Attempt at a Solution


62 - x = (1/2)*(0.21 m/s^2)t^2
62 - x = (1/2)*(0.26 m/s^2)t^2

I was trying to find any velocity or any time but i can't seem to conceive anything logic that would work. Any help would be greatly appreciated.
 
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Try to write equations that give the position of each knight relative to Sir George's starting position at any given time, and then find when they are equal.
 
Neil6790 said:

Homework Statement


In a historical movie, two knights on horseback start from rest 62 m apart and ride directly toward each other to do battle. Sir George's acceleration has a magnitude of 0.21 m/s2, while Sir Alfred's has a magnitude of 0.26 m/s2. How far from Sir George's starting point do the knights collide?

Homework Equations



The Attempt at a Solution


62 - x = (1/2)*(0.21 m/s^2)t^2
62 - x = (1/2)*(0.26 m/s^2)t^2

I was trying to find any velocity or any time but i can't seem to conceive anything logic that would work. Any help would be greatly appreciated.

Almost the right idea.
You need to use different X1 and x2

X1 = 1/2a1t2

X2 = 1/2a2t2

You know that they meet by definition when the time is equal and ...their total distance adds to 62.

Divide the first equation by the second.

You get X1/X2 = a1/a2

and you know X1 + X2 = 62.
 

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