Λa+µb+vc =0 constants not all zero c.(axb)=0

  • Thread starter Thread starter indie452
  • Start date Start date
  • Tags Tags
    Constants Zero
Click For Summary
SUMMARY

The discussion centers on the vector equation λa + µb + vc = 0, where λ, µ, and v are not all zero, and demonstrates that c.(axb) = 0. The solution involves analyzing two cases: when v is not equal to zero and when v equals zero. The key conclusion is that if v is not zero, then vc.(axb) must equal zero, leading to the result that c.(axb) = 0 by utilizing properties of the dot and cross product, confirming that axb is perpendicular to both vectors a and b.

PREREQUISITES
  • Understanding of vector algebra, specifically dot and cross products.
  • Familiarity with linear combinations of vectors.
  • Knowledge of vector properties in three-dimensional space.
  • Basic proficiency in solving vector equations.
NEXT STEPS
  • Study the properties of dot and cross products in vector calculus.
  • Learn about linear independence and dependence of vectors.
  • Explore applications of vector equations in physics and engineering.
  • Investigate the geometric interpretation of vector operations.
USEFUL FOR

Students studying linear algebra, mathematicians, and anyone interested in vector calculus and its applications in physics and engineering.

indie452
Messages
115
Reaction score
0

Homework Statement



past paper qu...

λa + µb + vc = 0
for some λ, µ, v not all zero show c.(axb)=0

consider cases v not equal to 0 and v = 0

The Attempt at a Solution



not sure how to start so if someone could just point me in the right direction or offer another hint it may help me get started in the mean time i'll keep looking at it

thanksok i think i made a bit of progress:-

when v not= 0
λa.(axb) + µb.(axb) + vc.(axb) = 0.(axb)

so vc.(axb) = 0
=> c.(axb) = 0
 
Last edited:
Physics news on Phys.org
Use properties of the dot and cross product. axb is perpendicular to both a and b, right?
So a.(axb)=b.(axb)=0. And if a and b are parallel, then axb=0.
 
Dick said:
Use properties of the dot and cross product. axb is perpendicular to both a and b, right?
So a.(axb)=b.(axb)=0. And if a and b are parallel, then axb=0.

ok this along with the progress i made earlier has helped me do the qu

thanks a lot :biggrin:
 

Similar threads

  • · Replies 22 ·
Replies
22
Views
3K
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 75 ·
3
Replies
75
Views
7K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 18 ·
Replies
18
Views
9K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K