1. The problem statement, all variables and given/known data A uniform ladder AB, of weight W and length 2.5m rests against a smooth vertical wall OA with its foot on smooth horizontal ground OB. The ladder is in a vertical plane perpendicular to the wall. It is kept in position with OA=2m and OB=1.5m by a light rope OC joining O to a point C on the ladder such that angle COB=theta. Show that the tension T in the rope is given by T=(3W)/(8cos(theta)-6sin(theta)) 2. Relevant equations This is just a moments question. 3. The attempt at a solution I've tried taking moments about B, but don't seem to get why there are two terms in theta in that equation.