Lagrange multipliers rotating masses connected by spring

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SUMMARY

The discussion focuses on deriving the equations of motion for two particles, m1 and m2, constrained to move in circular paths using Lagrange multipliers. The Lagrangian is formulated as L=T-V+λ1(-z1)+λ2(c-z2)+λ3(a²-x1²-y1²)+λ4(b²-x2²-y2²), where T represents the kinetic energy and V the potential energy. The resulting equations of motion are expressed in terms of the accelerations of the particles and the spring constant k. A suggestion is made to simplify the problem by using polar coordinates to reduce the number of equations.

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  • Understanding of Lagrangian mechanics
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  • Knowledge of kinetic and potential energy formulations
  • Basic concepts of polar coordinates
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  • Study the application of Lagrange multipliers in constrained systems
  • Learn how to convert Cartesian coordinates to polar coordinates
  • Explore the derivation of equations of motion from the Lagrangian
  • Investigate the effects of spring constants on motion in coupled systems
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Homework Statement



A particle of mass, m1, is constrained to move in a circle with radius a at z=0 and another particle of mass, m2, moves in a circle of radius b at z=c. For this we wish to write up the Lagrangian introucing the constraints by lagrange multipliers and solve the following equations of motion.

Homework Equations



Equations of constraint.

[tex]z1=0\ \ x1^2+y1^2=a^2[/tex]
[tex]z2=c \ \ x2^2+y2^2=b^2[/tex]

The Attempt at a Solution



I am working on the Lagrangian given by

[tex]L=T-V+\lambda_1\left(-z_1\right)+\lambda_2\left(c-z_2\right)+\lambda_3\left(a^2-x_1^2-y_1^2\right)+\lambda_4\left(b^2-x_2^2-y_2^2\right)[/tex]

with
[tex]T=\frac{1}{2}m_1\left(\dot{x}_1^2+\dot{y}_1^2+\dot{z}_2^2\right)+\frac{1}{2}m_2\left(\dot{x}_2^2+\dot{y}_2^2+\dot{z}_2^2\right)[/tex]
and
[tex]V=\frac{1}{2}k\left(\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2+\left(z_2-z_1\right)^2\right)[/tex]

From this we get the equations of motion:

[tex]m_1\ddot{x_1}=-k\left(x_2-x_1\right)-2\lambda_3x_1[/tex]

[tex]m_1\ddot{y_1}=-k\left(y_2-y_1\right)-2\lambda_3y_1[/tex]

[tex]m_1\ddot{z_1}=-k\left(z_2-z_1\right)-\lambda_1[/tex]

[tex]m_2\ddot{x_2}=k\left(x_2-x_1\right)-2\lambda_4x_2[/tex]

[tex]m_2\ddot{y_2}=k\left(y_2-y_1\right)-2\lambda_4y_2[/tex]

[tex]m_2\ddot{z_2}=k\left(z_2-z_1\right)-\lambda_2 [\tex]<br /> <br /> <br /> Anyone know how to solve these equations of motion[/tex]
 
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You could reduce the number of coordinates by introducing polar coordinates for each mass. There would be less equations to solve.
 

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