Lagrangian Dynamics Homework: Find Missing Term

Click For Summary

Homework Help Overview

The discussion revolves around a problem in Lagrangian dynamics, specifically addressing the missing term in the Lagrangian related to the kinetic energy of a pendulum in a moving frame of reference. Participants are exploring the implications of constraints on the system's degrees of freedom.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster suggests that a term related to the kinetic energy of the pendulum due to the horizontal movement of the carriage is missing from the Lagrangian. Some participants question the relevance of this term, indicating it may be a total derivative and thus irrelevant for the equations of motion.

Discussion Status

The discussion is ongoing, with participants providing clarifications regarding the constraints and degrees of freedom in the system. There is an exploration of how the constraint affects the Lagrangian, but no consensus has been reached on the necessity of the missing term.

Contextual Notes

Participants are working under the assumption that the motion of the pendulum is defined by a single degree of freedom, specifically the angle, and that the motion in the vertical direction is determined by the horizontal velocity function.

davon806
Messages
147
Reaction score
1

Homework Statement


New Bitmap Image (2).jpg


Homework Equations


The last part of this question is an example of this result:
C.jpg


The Attempt at a Solution


Here is the solution
a.jpg


I think L' is missing a term: If we take the Earth as your frame of reference.(i.e. You are stationary, watching the movement of the railway carriage).Then there should be an extra term for the KE of pendulum,due to horizontal movement of the carriage. (see below, the y dot term corresponds to v of the carriage)
b.jpg


Why is it not involved in L' ?
 
Physics news on Phys.org
Your constraint equation is ##\dot y = v(t)##. This implies that the term you are referring to only depends on t and therefore is a total derivative (and hence irrelevant for the equations of motion).
 
Orodruin said:
Your constraint equation is ##\dot y = v(t)##. This implies that the term you are referring to only depends on t and therefore is a total derivative (and hence irrelevant for the equations of motion).
Sorry, could you explain it in more detail? I couldn't get it
 
Which part do you have trouble with? There is only one degree of freedom for the pendulum, the angle ##\theta##. The final Lagrangian cannot depend on ##y## since the motion of ##y## is given by integrating ##v(t)##. The constraint gives you ##\dot y = v(t)## and so ##y(t)## is a primitive function of ##v(t)##. Inserting the constraint into your Lagrangian means your ##\dot y^2## term turns into
$$
\frac{\mu v(t)^2}{2}.
$$
This is a function of ##t## only and does not affect the equations of motion.
 
  • Like
Likes   Reactions: davon806

Similar threads

  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
3
Views
6K
  • · Replies 5 ·
Replies
5
Views
10K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K