Lagrangian for a particle moving in x-y plane in a constant B-field

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Homework Help Overview

The discussion revolves around deriving the Lagrangian for a particle moving in the x-y plane under the influence of a constant magnetic field. The original poster is attempting to understand the relationship between the Lagrangian equations and the resulting differential equations for the coordinates x and y.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster describes their attempts to solve the Lagrangian equations for x and y, leading to a system of differential equations. They express confusion about the subsequent steps, particularly in relating these equations to the complex variable z.
  • Some participants suggest setting z = x + iy and using the derived equations to form a new differential equation for z.
  • Others question how to manipulate the equations for x and y to derive the equation for z, specifically whether multiplying one equation by i and adding them would be beneficial.
  • Further inquiries arise regarding the interpretation of complex constants X and Y in the context of the solution.

Discussion Status

Contextual Notes

Participants note the complexity of the solution provided and the difficulty in reading certain parts. There is also mention of boundary conditions that may influence the values of z, x, and y at specific times, which are relevant to the problem but not fully resolved in the discussion.

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Homework Statement


Not sure if the link is showing. But it's imgur.com/a/LEvd0
LEvd0

LEvd0

Homework Equations


The steps I've taken so far as written in the attempt section below is correct.

The solution provided then proceeds with letting ##z = x + iy## and setting ##\ddot z+i \omega \dot z = 0##. Then ##z(t)=X\exp(-i\omega t) + Y## where X, Y are complex.
Lastly, ##X=Aexp{(i\omega t)} * \text{something illegible}## and ##Y=D+iE## and then says this leads to the x and y equations shown in the question.

The Attempt at a Solution


We first solve the lagrangian equation by splitting x and y terms. So for x:
$$\frac{d}{dt} \frac{\partial L}{\partial \dot{x} } - \frac{\partial L}{\partial x} = 0$$
and $$\ddot x -\omega \dot y =0.$$
Similarly for y:
$$\ddot y +\omega \dot x= 0$$

I'm not quite sure what to do after this step. As explained in the previous section, the solution sets ##z=x+iy## but the steps afterwards are very unclear and hard to read.

Any help will be appreciated.
 
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Step 1: Set z = x + iy, use the two differential equations you got for x and y, to get the differential equation for z. You can proceed from there.
 
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Chandra Prayaga said:
Step 1: Set z = x + iy, use the two differential equations you got for x and y, to get the differential equation for z. You can proceed from there.
That's the part where I'm confused. How would I incorporate the x and y differential equations to z=x+iy?
 
Can you multiply one of the two equations with i and then add the two equations? Will that help?
 
Chandra Prayaga said:
Can you multiply one of the two equations with i and then add the two equations? Will that help?
Thank you.

Multiply i to the y DE and add the two equations so:
$$ \ddot x - \omega \dot y + i\ddot y +i\omega \dot x =0. $$
Rearrange and it becomes
$$\ddot z +i\omega \dot z = 0.$$
Does this then imply
$$\dot z + i\omega z = Y$$ where Y is complex?
Then solving for z leads to $$z = X\exp(i\omega t) +Y$$ where X and Y are complex (the Y here is different by a factor from Y before but still a complex).

Now, another part I am confused is, the solution says Y can always be written as Y = D+iE which I understand since it's a complex, but it also says X can be written as something like ##A\exp(iωt_a)+C\exp(iωt_b)## but I can't really read off what it says. To conform with the solutions of x and y given, what could this X be?
 
Use the boundary conditions. z = x + iy, and both x and y are specified for two values of t. That will give you the value of z at those times. Compare that with the solution that you got above for z. That should give you X nd Y
 

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