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I'm not sure how to obtain the kinetic and potential energies. For the potential energy, would it just be

[tex]V=mglcos\theta+Asin\omega t[/tex]?

And is the kinetic energy

[tex]T=\frac{1}{2}m(l^{2}\dot{\theta}^{2}+A^{2}\omega^{2}cos^{2}\omega t)[/tex]?

Since the Lagrangian wouldn't be time-independent, would this in any way affect the Euler-Lagrange equation, or would it remain the same?

Thanks, all.