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Lagrangian of System: K.E.=0, V=-mgl
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[QUOTE="hilbert2, post: 5635158, member: 482973"] There's no way for that system to be in equilibrium unless there's static friction or if the chain is being pulled from the left side end. If you want to use the formula ##V = mgh## for the potential energy, you must interpret ##h## as the vertical (z) coordinate of the center of mass of the chain. If we set ##z=0## on the top of the table, what is the ##z## coordinate of the CM? [/QUOTE]
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Lagrangian of System: K.E.=0, V=-mgl
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