Laplace equation w/ dirichlet boundary conditions - Partial Diff Eq.

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 2K views
bossman007
Messages
60
Reaction score
0

Homework Statement



The steady state temperature distribution [tex]T(x,y)[/tex] in a flat metal sheet obeys the partial differential equation:

[tex]\displaystyle \frac{\partial^2 T}{\partial x^2}+ \frac{\partial^2 T}{\partial y^2} = 0[/tex]

separate the variables in this equation just like in the one-dimensional wave equation and find T everywhere on a square flat plate of sides S with the boundary conditions:

[tex]T(0,y)=T(S,y)=T(x,0) , T(x,S)=T_0[/tex]

Homework Equations


The Attempt at a Solution



this is what I have so far..not sure what to do next?

[url=http://postimage.org/image/k0ujzisqz/][PLAIN]http://s17.postimage.org/k0ujzisqz/steady_state_heat_prob.jpg[/url][/PLAIN]
 
Last edited:
Physics news on Phys.org
I'm not bumping my post, sorry! I forgot to mention that classmates mentioned [tex]sinh[/tex] shows up in the Fourier series and I don't know why also. Any help getting started would be greatly appreciated

many thanks
 
The differential equation for Y(y) has a sign mistake in it, though the solutions you wrote down are correct. Instead of exponentials, you can write down the solution in terms of the hyperbolic functions
\begin{align*}
\cosh ky &= \frac{e^{ky}+e^{-ky}}{2} \\
\sinh ky &= \frac{e^{ky}-e^{-ky}}{2}
\end{align*} It's analogous to how you can write down the solutions for X(x) in terms of sin kx and cos kx or in terms of eikx and e-ikx. You're just choosing a different basis.

Now you have to apply the boundary conditions.