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Laplace transform of (2s^2 +10s) / ((s^2 -2s +5)(s+1))

  1. Mar 14, 2016 #1
    1. The problem statement, all variables and given/known data
    (2s^2) +10s / (s^2 -2s +5 )(s+1) , I have checked the partial fraction , it's correct , but according to the ans it's (e^t)[(3cos2t + 2.5sin2t)] - (e^-t), but my ans is (e^t)[(3cos2t + 4sin2t)] - (e^-t)


    2. Relevant equations


    3. The attempt at a solution
    UsCyv8m.jpg
     
  2. jcsd
  3. Mar 14, 2016 #2

    Ray Vickson

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    You typed
    [tex] 2s^2 +\frac{10s}{(s^2 -2s +5 )(s+1)} [/tex]
    If you mean
    [tex] \frac{2s^2 + 10s}{(s^2-2s+5)(s+1)},[/tex]
    you must either use LaTeX (as I did just now) or else use parentheses, like this:
    (2s^2+ 10s)/[(s^2-2s+5)(s+1)]

    Anyway, that form gives an inverse Laplace that agrees with your answer.
     
  4. Mar 14, 2016 #3
    Sorry, I mean the second one. You mean my answer is correct??
     
  5. Mar 14, 2016 #4

    Ray Vickson

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    Isn't that what I said?
     
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