Laplace Transform of t u(t-2) using Basic Definition

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To find the Laplace transform of g(t) = t u(t-2) using the basic definition, the integral is set up from 2 to infinity, resulting in L{f(t)} = ∫_2^∞ t e^(-st) dt. The Heaviside function H(t-2) indicates that the function is zero for t < 2 and one for t ≥ 2, allowing the integration to start at t = 2. A user successfully applied the t-shifting property but sought clarification on using the basic definition. Additionally, there was a query about the inverse Laplace transform of 1, indicating interest in understanding its implications.
tommyhakinen
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Homework Statement


find the laplace transform of g(t) = t u(t-2) using the basic definition.


Homework Equations


L{f(t)} = ∫f(t)e-stdt from 0 to infinity

The Attempt at a Solution


I am able to get the transform by applying the t-shifting property. However, how do I do it by using basic definition? thanks.
 
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tommyhakinen said:

Homework Statement


find the laplace transform of g(t) = t u(t-2) using the basic definition.


Homework Equations


L{f(t)} = ∫f(t)e-stdt from 0 to infinity

The Attempt at a Solution


I am able to get the transform by applying the t-shifting property. However, how do I do it by using basic definition? thanks.
By integrating! Since H(x) is defined to be 0 for x< 0, 1 for x>= 0, H(t-2)= 0 for t< 2, 1 for t<= 2.
L{f(t)}= \int_2^\infty t e^{-st}dt
That should be easy.
 
Thank you very much. One more question. what is the inverse laplace transform of 1? Is it possible to get it? if there is, what can be done? thanks..
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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