Laplace transform sqaured differential

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 3K views
opul
Messages
1
Reaction score
0
Hi

I was wondering what the Laplace transform of a squared differential is.
With that I mean the Laplace of (y' )^2 (this being y'*y' and not the second order derivative). So for example velocity squared.
 
Physics news on Phys.org
there is a lot of similarity between the Fourier Transform and the Laplace Transform. the F.T. is really just the L.T. with the real part of [itex]s = \sigma + i \omega[/itex] set to zero. try to answer the question regarding the F.T. and see if you can generalize.
 
I don't know the exact form off the top of my head, but it will be an ugly convolution of the form:

integral (s^2 F(a)F(a-s) da)