Laplace Transform: sin2(t-1)U(t-1) - Correct Answer?

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SUMMARY

The Laplace transform of the function sin²(t-1)U(t-1) is definitively expressed as \(\frac{2e^{-s}}{s^2 + 4}\). The initial incorrect formulation \(\frac{2e^{-s}}{s^2} + 4\) was clarified and corrected in the discussion. The unit step function U(t-1) plays a crucial role in shifting the function, which is essential for accurate transformation. This correction is vital for anyone working with Laplace transforms in engineering or applied mathematics.

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  • Understanding of Laplace transforms
  • Familiarity with the unit step function U(t)
  • Basic knowledge of trigonometric functions, specifically sin²(t)
  • Experience with exponential functions in mathematical contexts
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Students, engineers, and mathematicians who are working with Laplace transforms, particularly in the context of control systems and differential equations.

magnifik
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what is the Laplace transform of sin2(t-1)U(t-1)
(U is the unit step function)

i got 2e-s/s2 + 4
is this correct?
i'm unsure about the exponential part
 
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Yup, that's right. I'm assuming you actually meant

\frac{2e^{-s}}{s^2+4}

as opposed to

\frac{2e^{-s}}{s^2}+4

which is what you actually wrote.
 

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