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Susanne217
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Homework Statement
I am given the following
[tex]f(t)= e^t[/tex] where 0<t<2
express the function f(t) in the terms of the unitstep func.
Homework Equations
I am told that the f(t) can be expressed
[tex]\mathcal{L}(f(t-a)u(t-a)) = e^{-as}F(s) [/tex]
The Attempt at a Solution
where [tex]F(S) = \mathcal{L}(f(t))[/tex]
then
[tex]\mathcal{L}(f(t-0)u(t-0)) = \frac{1}{s} [/tex]
and
[tex]\mathcal{L}(f(t-2)u(t-2)) = e^{-2s} \frac{1}{s-1} [/tex]
I am told that I need to add the two together (what is my motivation for doing this?)
and if I do this I get
[tex]\mathcal{L}(F(s)) =\frac{1+e^{-2s}}{s(s-1)}[/tex]
what am I doing wrong here?
Best Regards
Susanne
edit: I have discovered that if I take the place integral
[tex]\mathcal{L}(f(t)) = \int _{0}^{2} e^{-st} \cdot e^{t} dt = \frac{e^{t-st}}{1-s}|_{t=0}^{2} = \frac{1-e^{2-2s}}{1-s}[/tex]
which is desired result according to the textbook. But how do I show that this can the found using the original method above?
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