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Laplace transforms to solve linear ODE's

  1. Feb 14, 2013 #1
    *edit* can't upload images from phone with app for some reason, finding a computer.

    Using the app for the first time so hopefully this works out ok..

    I've attached an image with the problem written in blue, and a complete attempt in gray. I have the answer to the question however it is completely different to mine..

    Also, relevant equations are in the gray box on the right (the first line for each, the second is with the values subbed in).

    I think it's correct up until the line where I first get L[y] on its own. But I could be wrong..
     

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    Last edited: Feb 14, 2013
  2. jcsd
  3. Feb 14, 2013 #2

    vela

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    If you want help, you should make your post convenient for the helpers to read.
    You're right. You made an algebra mistake in simplifying L[y] when you got rid of s2 in the denominator. You can't do what you did.
     
  4. Feb 15, 2013 #3
    Hi, thanks for the reply, and sorry about the format, I honestly thought that would be ok having the question and attempt all in one place.

    As for the mistake, I had a feeling I couldn't do that, however I don't really know how else I could do it.. my basic arithmetic/algebra skills are really holding me back.

    My idea was to try and factorise it so that I could eliminate one of the denominators but I can't see the factor..
     
  5. Feb 15, 2013 #4

    Mute

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    The problem with your original post was that your picture was a) sideways and b) relatively small, making it hard to read your work. vela was just letting you know that that kind of post is not likely to receive replies because it's a fair amount of extra work for the homework helpers to read your work properly before they can help you. Not everyone is willing to retype out your entire problem like vela did. :)

    For your problem, one method you could try is to first write your fraction as two terms like so:

    $$\frac{4s^3 - 9s^2 + 4}{s^2(s-2)(s-1)} = \frac{4s^3-9s^2}{s^2(s-2)(s-1)} + \frac{4}{s^2(s-2)(s-1)}.$$

    You can cancel the s^2 in the first term, but it sticks around in the second term. You can then perform the partial fraction decomposition on each term separately. Does that help?
     
  6. Feb 15, 2013 #5

    vela

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    I recognize it's often more convenient for students to simply post an image of their work, but from the helper's perspective, it can be annoying because you often end up having to open the image in a separate window to make it big enough to read and then you have to switch back and forth between windows as you compose your reply. Sometimes I'll skip posts like those because I don't want to be bothered with doing that, and I know some of the other helpers around here do that as well. At the very least, you should at least type the problem in directly so we don't have to open an image just to see what the thread is about.

    You're at a point where you really need to have the basics down cold, otherwise you end up wasting a lot of time chasing down avoidable mistakes (as you already seem to recognize). It might not hurt to go back to spend a little time reviewing some of it. What seemed like random rules back when you first learned them might make more sense to you now.

    The standard partial fraction expansion is
    $$\frac{4s^3-9s^2+4}{s^2(s-2)(s-1)} = \frac{A}{s-2} + \frac{B}{s-1} + \frac{Cs+D}{s^2}.$$ When you have a quadratic factor on the bottom, you need a linear term on top instead of just a constant.
     
  7. Feb 15, 2013 #6

    Mark44

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    I agree completely. We homework helpers and mentors are all volunteers, helping out because we enjoy doing it, but when it becomes too much work to help someone, some of us just say to heck with it.
    Yes, 100%.
    Good advice.
     
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