Laplacian cylindrical coordinates

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
LagrangeEuler
Messages
711
Reaction score
22
Laplacian in cylindrical coordinates is defined by

[tex]\Delta=\frac{\partial^2}{\partial \rho^2}+\frac{1}{\rho}\frac{\partial}{\partial \rho}+\frac{1}{\rho^2}\frac{\partial^2}{\partial \varphi^2}+\frac{\partial^2}{\partial z^2}[/tex]
I am confused. I I have spherical symmetric function f(r) then
[tex]\Delta f(r)=\frac{d^2}{dr^2}f(r)+\frac{2}{r}\frac{d}{dr}f(r)[/tex]
If I worked on function ##f(r)## with Laplacian in cylindrical coordinates. I suppose that [tex]f(r)=f(\rho)[/tex] but then factor ##2## is problem.
 
Physics news on Phys.org
Of course. Thanks.