Largest Cylinder Volume in Cuboidal Log: What is the Maximum Possible Volume?

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Homework Help Overview

The discussion revolves around determining the volume of the largest cylinder that can be extracted from a cuboidal log with specified dimensions. The problem involves understanding the geometric constraints imposed by the dimensions of the cuboid.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the radius and height of the cylinder, questioning the original poster's choice of radius. There is an exploration of how the dimensions of the cuboid affect the maximum possible radius and volume of the cylinder.

Discussion Status

Participants are actively engaging with the problem, providing feedback on the original poster's calculations and suggesting that the radius should be maximized. There is an acknowledgment of the limitations posed by the cuboid's height in relation to the cylinder's diameter.

Contextual Notes

There are constraints related to the dimensions of the cuboid, particularly the height, which affects the possible diameter of the cylinder. The discussion also touches on the need for visual aids, such as diagrams, to better understand the spatial relationships involved.

Amith2006
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Homework Statement


What is the volume of the largest cylinder that can be cut out of a cuboidal log of
wood of dimensions 30*20*10 inches?

Homework Equations


volume of cuboid = length*breadth*height
volume of cylinder= *[radius]²*height


The Attempt at a Solution



Radius of largest cylinder=5 inches
height of largest cylinder=30 inches
volume of largest cylinder=750 inch³
But book answer is 1000.
 
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Hi Amith2006! :smile:
Amith2006 said:
volume of cylinder= *[radius]²*height

Yes, the radius is squared but the height is on its own.

So don't you you want the radius to be as large as possible?

ooh … got to go now … Doctor Who starting on telly! :biggrin:
 
tiny-tim said:
Hi Amith2006! :smile:


Yes, the radius is squared but the height is on its own.

So don't you you want the radius to be as large as possible?

ooh  got to go now  Doctor Who starting on telly! :biggrin:


so doed it seem ok?
 
Amith2006 said:
so does it seem ok?

No!

You want the radius to be as large as possible,

but you've made it the smallest possible (5).

Try again, and see the difference! :smile:
 
tiny-tim said:
You want the radius to be as large as possible,

but you've made it the smallest possible (5).

:smile:

The problem that i face is that i can't cut out a circle of diameter 20 inches because the height is only 10 inches. i can only do so by making the Cross Section oval.
 
Amith2006 said:
The problem that i face is that i can't cut out a circle of diameter 20 inches because the height is only 10 inches. i can only do so by making the Cross Section oval.

No … draw a diagram … 6 bricks in two layers of 3.

One side is 2 bricks x 3 bricks.

Draw the circle on that side! :smile:

(btw, what happened to π in the formula?)
 

thanx.
 

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