Last part of question on continuous functions

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SUMMARY

The discussion focuses on proving that if a function h: (0,1) is continuous, then h(x) ≤ h(y) for all x, y ∈ (0,1) where x ≤ y. The user is tasked with using the definition of continuous functions and the Intermediate Value Theorem to establish this relationship. Additionally, a counterexample is requested to demonstrate that continuity does not guarantee the inequality holds in all cases. The conversation highlights the importance of understanding the implications of continuity in real analysis.

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Homework Statement


This is the last part of a revision question I'm trying, would really like to get to the end so any pointers or help would be greatly appreciated.

Suppose h:(0,1)-> satisfies the following conditions:
for all xЭ(0,1) there exists d>0 s.t. for all x'Э(x, x+d)n(0,1) we have h(x)<=h(x')

Prove that if h is continuous on (0,1) then h(x)<=h(y) whenever x.yЭ(0,1) and x<=y. Use a counterexample to show that this results may not be true when h is continuous.

Homework Equations


Well, definition of continuous functions,
also above in the question i am asked to state the intermediate value theorem so i think perhaps i am meant to use that.


The Attempt at a Solution



if h is continuous on (0,1) then for all cЭ(0,1), for all E>0, Эd s.t. for all xЭ(0,1), 0<|x-c|<d this implies that |h(x)-h(c)|<E
i really just don't see how to continue. Any help would be great. Thank you
 
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Try fixing x, and showing that for every value of y larger than it, h(x)<=h(y)
 

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