- #1
trying_mybest
- 10
- 4
- Homework Statement
- I'm supposed to calculate the latent heat of fusion of water from the given experimental data.
6 ice cubes, each weighing 4 g, were used to bring the temperature of a 0.25-L water from 23.3˚ C to 0˚ C. The temperature of each ice cube is assumed to be -15˚ C.
- Relevant Equations
- Not sure if these are the correct equations to use:
Q = m * Cv * ∆T
Q = m * Lf
Q1 = m(ice) * Cv * ∆T = amount of heat the ice absorbs
Q2 = m(H2O) * Lf = amount of heat the water loses
Q2 = m(H2O) * Lf = amount of heat the water loses
- Q1 = (4*8 g) * (2198 J/g*K) * (0-(-15)) = 1.055 * 10^6 J
- Q1=Q2
- Q2 = 1.055 * 10^6 J = m(H2O) * Lf
- Lf = 1.055 * 10^6 J / m(H2O) = 1.055 * 10^6 J / (0.25 L * 1000 g/1L) = 4220 J/g