A window of a car is found to be covered with 0.8cm of ice. If the area of the window is 1 m2, and the ice is at -12 degrees Celsius, what is the minimum heat required to melt all the ice? Take the density of ice to be 900 kg/m3, the specific heat capacity of ice to be 0.5 cal/g*K, and the latent heat of fusion to be 80 cal/g. Answer in kcal.[/B]
Latent Heat= deltaQ= Lm[/B]
The Attempt at a Solution
So first off, I am confused in terms of finding out the mass to use. I wasnt sure if it is .512 g by multiplying .8x.8.x8 for cm3, or if you are supposed to make 0.8cm into meters then get the volume of that and multiply it by 900kg/m3 and then make kg into grams. If it is the second method, then the mass would be .46 grams?
So then what i tried doing is add Q1 and Q2 to each other. Q1 for me was (0.512)(.5 cal/g K)(12) and then Q2 i have as (80 cal/g)(.512) Then i added these together to get 44.032 calories which would be 0.044032 kcal. This answer does not seem right however and I feel like it is too low. What am I doing wrong? Thank You So much