How many ice cubes were added to cool the pool to 17°C?

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Homework Help Overview

The problem involves a physics scenario where a grad student adds ice cubes to a pool of water to cool it from 26°C to 17°C. The pool contains 156 liters of water, and the ice cubes are initially at 0°C. The discussion revolves around calculating the number of ice cubes required to achieve the desired temperature, considering the specific heat capacities and latent heat of fusion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculations for heat transfer between the water and ice, questioning how to incorporate the latent heat of fusion and the specific heat of melted ice. There is confusion regarding the correct application of the heat equations and the role of the heat capacity of ice.

Discussion Status

Some participants have provided insights into the necessary calculations, indicating that all ice cubes melt and absorb heat before the resulting water warms to 17°C. However, there is still uncertainty about the correct approach to combine the heat absorbed by the ice and the heat lost by the water.

Contextual Notes

Participants are working under the assumption that the system is isolated, and there are discussions about the implications of the latent heat of fusion in the calculations. Some participants express confusion about the steps needed to arrive at the correct answer.

cyberdx16
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Homework Statement


Trying to beat the heat of summer, a physics grad student went to the local toy store and purchased a child's plastic swimming pool. Upon returning home, he filled it with 156 liters of water at 26°C. Realizing that the water would probably not be cool enough, he threw ice cubes from his refrigerator, each of mass 30 g, into the pool. (The ice cubes were originally at 0°C.) He continued to add ice cubes until the temperature stabilized at 17°C. He then got in the pool.

The density of water is 1000 kg/m3, the specific heat of water is 1.0 cal/g °C, the specific heat of ice is 0.5 cal/g °C, and the latent heat of fusion of water is 80 cal/g.

How many ice cubes did he add to the pool to get the temperature to 17°C? (Consider the pool and ice cubes an isolated system.)

Homework Equations



Q=mc(DeltaT)
Qwater/Qice=# of ice cubes

The Attempt at a Solution



Mass water=1000*.156=156kg
Qwater=156000g(1.0 cal/g*degree Celsius)(17-26)=-1404000cal
QIce=30g(.5 cal/g*degree Celsius)(17-0)=255cal

now do i neglect the negative in Qwater? so then i would get 1404000cal/255cal=5505.88cubs but is not the correct answer

I don't understand what i have to do with the latent heat of H2O fusion(80cal/g)
 
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All of the cubes melted. Each gram of ice absorbed 80 cal/gm of heat as it melted and THEN the resulting WATER warmed up to 17 degrees. In fact, the heat capacity of ice has nothing to do with the problem.
 
Dick said:
All of the cubes melted. Each gram of ice absorbed 80 cal/gm of heat as it melted and THEN the resulting WATER warmed up to 17 degrees. In fact, the heat capacity of ice has nothing to do with the problem.

I still have no clue wtf is going on... now would i use the equation Q=mL for the ice? that would give me 2400cal... Then take the Qw=1404000/Qice=2400? but that gives me 585, which is not the correct answer
 
There are two parts in Qice. One of them you just computed. To get the other one you have to heat the melted water up 17 degrees. Then you have to add them.
 
alright gotcha! i guess i didnt take into consideration that ice metals and turns to h20 (l) and heats up to 17C
 

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