Path of a ball thrown radially from a satellite orbiting Earth

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SUMMARY

A ball thrown radially downwards at 20 m/s from a satellite in a circular orbit 500 km above Earth will follow a slightly elliptical path relative to Earth. The satellite's orbital velocity is calculated to be 7667.7 m/s using the equation mv²/r = GMm/r². Upon being thrown, the ball will initially move in reverse relative to the satellite due to its lower velocity, but it will maintain its tangential speed. Consequently, the ball will gain on the satellite as its trajectory circumference is smaller than that of the satellite's orbit.

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Homework Statement


A satellite has a circular orbit 500 km above earth. A ball is thrown directly downwards radially at 20 m/s. Find the path of the ball relative to the satellite.

Homework Equations



mv^2/r=GMm/r^2

The Attempt at a Solution


From the height of the orbit you can easily solve for the velocity:
mv^2/r=GMm/r^2=>v_{satellite}=sqrt{GM/r}=7667.7 m/s

Now I can easily tell that the ball is just going to take a slightly elliptical path relative to EARTH, however I can't quite figure out (conceptually or mathematically) what this path will take relative to the satellite moving in a circular orbit.

From what I can tell, immediately when the ball is thrown downwards, it will go in reverse (slightly) relative to the satellite because it won't be able to speed up again to the original velocity of the satellite. Any thoughts?

Thanks in advance!
 
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I would expect it to maintain tangential speed, because there's nothing to change that...
And then the ball at least initially would gain on the satellite because circumference of the trajectory is less... :-)
 

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