Law of conservation of energy help

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SUMMARY

The discussion centers on applying the law of conservation of energy to determine the initial speed of a pen sliding across a desk. The pen, with a mass of 0.057 kg, experiences a kinetic friction force of 0.15 N over a distance of 0.25 m, resulting in a final speed of 5.7 cm/s. The calculations confirm that the initial speed (Vi) of the pen is 1.1 m/s, derived from the energy equations Eth = Fk deltaD and deltaEk = 1/2mv^2f - 1/2 mv^2i. The steps taken in the solution are validated as correct, including unit conversions.

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Homework Statement



A pen of mass 0.057 kg slides across a horizontal desk. In sliding 25 cm, its speed decreases to 5.7 cm/s. The force of kinetic friction exerted on the pen by the desk has a magnitude of 0.15N. Apply the law of conservation of energy to determine the initial speed of the pen.

Homework Equations


Eth = Fk deltaD
deltaEk = 1/2mv^2f - 1/2 mv^2i
Eth = delta Ek

The Attempt at a Solution



Eth = (.15)(0.25)
= 0.0375 J

DeltaEk = 1/2(0.057)(0.057) - 1/2(0.057)Vi^2
= 9.25965x10^-5 - 0.0285 Vi^2

Eth = DeltaEk
0.0375 J = 9.25965x10^-5 - 0.0285 Vi^2

Vi = sqrt ((0.0375 - 9.25965x10^9)/0.0285)
Vi = 1.1 m/s

I get the right answer but i am not sure if i used the right steps.. can you please check my steps.. thx
 
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The notation is different than I am used to, but it looks like all the steps are correct, even the unit conversions. (Which is normally the part that people miss)

Good job!
 


okay.. thank you
 

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