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LC-3 Assembly Code Error detection

  • #1

Homework Statement



What is wrong with the code fragment:
.ORIG x3000
AND R0,R0, #0
AND R2,R2, #0
ADD R2,R2, #7
JSR SUB
ADD R2,R2, ASCII
ADD R0,R2,#0
TRAP x21
SUB ADD R2,R2,#9
ADD R7,R7,#1
RET
ASCII .FILL x0030
.END

The Attempt at a Solution



Ok, so first we ckear some register values. Then we set R2 to 7. Next we go into a subroutine that adds 9 to R2, so now R2 is 16. Then we add 1 to R7, which has an unknown value at the start. Then we return to the command after JSR. This adds the value in ASCII to R2, making R2 64. Then we set R0 to 64 as well, and finish by executing Trap x21.

I don't know what the problem here is, nor what the output is. I think Trap x21 does something with the keyboard to monitor, but I'm not sure.
 

Answers and Replies

  • #2
rcgldr
Homework Helper
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I think Trap x21 does something with the keyboard to monitor, but I'm not sure.
Trap x21 outputs to the monitor, then returns. R7 is used for the return address. What is going to happen with your program when trap x21 returns?

link to lc-3 instruction set pdf:

http://classes.soe.ucsc.edu/cmpe012/Summer09/notes/06_LC3_ISA_and_Addressing_Modes.pdf

link to assembly language pdf:

http://classes.soe.ucsc.edu/cmpe012/Winter09/lectures/06_LC3_Assembly.pdf

link to lc-3 trap pdf:

http://classes.soe.ucsc.edu/cmpe012/Summer08/notes/11_LC3_TRAP_markup.pdf

link to another description of the instruction set:

http://www.scribd.com/doc/4596293/LC3-Instruction-Details
 
Last edited:

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