A fixed inductance 0.66 [tex] \mu H [/tex] is used in series with a variable capacitor in the tuning section of a radio. What capacitance tunes the circuit into the signal from a station broadcasting at 8.11 MHz? Answer in units of pF.(adsbygoogle = window.adsbygoogle || []).push({});

I used the equation [tex] \omega = 1/ \sqrt LC [/tex]

Solving for C gave me [tex] (1/ \omega)^2 /L [/tex]

Then I converted all my numbers.

0.66[tex] \mu H [/tex] = 6.6e-7 H

8.11 MHz= 8110000 Hz

So plugging in, (1/8110000)^2 / 6.6e-7

gave me 2.30e-8 F

then converting to pF, gave me 23000, which isn't right.. can someone tell me what I'm doing wrong?

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# Homework Help: LC circuit and fixed inductance problem

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