Leaping Frog Game: Investigating # of Moves for n & m Frogs

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Homework Help Overview

The discussion revolves around the Leaping Frog Game, where participants investigate the number of moves required for different configurations of frogs, specifically focusing on the number of frogs on each side and the resulting moves needed to complete the game.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster shares calculated moves for various configurations of blue and green frogs, suggesting a potential formula for determining moves based on the number of frogs. Other participants explore strategies for moving frogs and question the total number of spaces moved through and the relationship between jumps and total moves.

Discussion Status

The discussion is ongoing, with participants sharing observations and strategies. Some guidance has been offered regarding potential strategies for moving frogs, but there is no explicit consensus on the optimal approach or the validity of the proposed formulas.

Contextual Notes

Participants note that the proposed formulas may not apply when the number of frogs on each side is uneven, and there are mentions of patterns observed in the game that require further explanation.

Natasha1
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I wandered if anyone could give me as much as possible info on the task I need to investigate at:

http://maths.fallibroome.cheshire.sch.uk/leapfrog.swf

I have worked out that frog 3 blue frogs and 3 green frogs it will take me 15 moves.

I have worked out that frog 3 blue frogs and 4 green frogs it will take me 19 moves.

I have worked out that frog 4 blue frogs and 4 green frogs it will take me 24 moves.

I have worked out that frog 4 blue frogs and 5 green frogs it will take me 29 moves.

I have worked out that frog 5 blue frogs and 5 green frogs it will take me 35 moves.

If n represents the number of frogs in a team then:

For:
n = 1 we have 3 = n * 3 moves
n= 2 we have 8 = n * 4 moves
n = 3 we have 15 = n * 5 moves
n = 4 we have 24 = n * 6 moves
n = 5 we have 35 = n * 7 moves
n = 6 we have 48 = n * 8 moves

Or more generally if there are n frogs on each side, then the minimum number of moves will be n*(n+2)

This formula does not work if the number of frogs in each team is uneven

If n represents the number of frogs in a team and m the number of frogs in the other then:

For:
n = 1 and m = 6 we have 13 = 1 * 6 + 1 + 6 moves
n = 4 and m = 3 we have 19 = 4 * 3 + 4 + 3 moves
n = 2 and m = 1 we have 5 = 2 * 1 + 2 + 1 moves
n = 5 and m = 6 we have 41 = 5 * 6 + 5 + 6 moves
n = 5 and m = 5 we have 35 = 5 * 5 + 5 + 5 moves

So if there are n frogs on one side and m on the other, then the minimum number of moves will be n*m+n+m

Other patterns notices but I can't explain why (please help!)

- For each frog extra that one team has, there will be a repetition of the jumps and slides. The string of jumps and slides is also symmetric.
- If there are the same number of frogs in each team, then each frog will have to move n+1 times.
 
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No one? :-(
 
Well, from playing that there appears to be a simple strategy, namely:
1. Let A = blue and B = green
2. Make all possible jumps of color A over color B
3. Make the one non-jumping move of color A.
4. Exchange colors A and B and repeat from step 1
You could probably prove that this works by induction though I suspect you might have a hard time showing that it's optimal.
 
How many total spaces have to be moved through? How many jumps will there be, and how will these reduce the number of moves required to reach the above total number of spaces?
 

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