Length Contraction Problem for a Rod in a Spaceship

Click For Summary

Homework Help Overview

The discussion revolves around a length contraction problem involving a rod moving in a spaceship, with considerations of relative motion and observer perspectives in the context of special relativity.

Discussion Character

  • Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the implications of the rod's motion relative to the spaceship and question the assumptions about the rod being at rest in the spaceship's frame.

Discussion Status

Some participants express agreement on the rod being at rest in the spaceship, while others raise concerns about the lack of explicit information regarding the rod's motion relative to the spaceship. This indicates an ongoing exploration of the problem's assumptions.

Contextual Notes

There is uncertainty regarding the velocity of the spaceship relative to the rod, which affects the interpretation of the problem. The original statement mentions the rod's velocity relative to the Earth, adding complexity to the assumptions being discussed.

Skyxplorer
Messages
2
Reaction score
0
Homework Statement
A rod has length of 1m. It is moving in a spaceship with velocity 0.4c relative to the earth. The length of the rod measured by an observer in the spaceship will be

(A) 1m

(B) 0.9m

(C) 0.5m

(D) 0.25m
Relevant Equations
-
Shoudnt answer be A since for observer in spaceship rod is at rest.
 
Physics news on Phys.org
Yes
 
Thank you for confirming
 
One might take is as a good assumption, but nowhere do I see it mentioned that the rod is at rest relative to the spaceship.

(In fact, it kind of says "it (the rod) is moving in a spceship" so I wouldn't be too quick with that assumption.)
 
  • Like
Likes   Reactions: berkeman
DaveC426913 said:
One might take is as a good assumption, but nowhere do I see it mentioned that the rod is at rest relative to the spaceship.
In fact it clear from the statement that it (the rod) is moving
Skyxplorer said:
##\dots## with velocity 0.4c relative to the earth.
It is safe to assume that the observer is at rest relative to the spaceship, but we are not told the velocity of the spaceship (and observer) relative to the rod.

Answer (B) is consistent with the spaceship being parked on the Earth and the rod passing through two diametrically opposing openings at 0.4c but that's stretching it. :oldsmile:
 

Similar threads

  • · Replies 36 ·
2
Replies
36
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 44 ·
2
Replies
44
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
2K