Length Contraction Relativity Question

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SUMMARY

The discussion revolves around the concept of length contraction in the context of special relativity, specifically addressing a scenario where an airplane is measured at a speed of 900 km/h. The formula used for calculating the moving length is Lmoving = Lrest x SQR[1 - (V/C)^2]. The participant initially concludes that there is no contraction because the speed is not close enough to the speed of light (c). However, it is clarified that while the contraction effect is minimal at this speed, it is still calculable. The discussion also suggests utilizing Taylor's expansion for more accurate results.

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  • Understanding of special relativity concepts
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goldilocks
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Hello, I am not sure if I am doing this right or not. It seems to simple to be the right aswer, I feel I must have gone wrong somewhere. Many thanks :-) xxx

Homework Statement



Length Contraction Relativity Question?

An aeroplane is of length L’(m) precisely when measured in its rest frame at the airport. In what percentage it will contract if measured by the same ground-based observer if it was flying past at 900 km.p.h?
[Here you may need Taylor’s expansion]


Homework Equations



Lmoving= Lrest x SQR[1 - (V/C)^2]

The Attempt at a Solution



I have tried to start this. I used Lmoving= Lrest x SQR[1 - (V/C)^2]

Lrest = L'(m)

Lmoving = L'(m)
= L'(m) x SQR(1-(250^2/(3x10^8)^2)
= L'(m) x SQR (1- 6.9445x10^-13)
= L'(m) x SQR (1)
= L'(m)

So there is no contraction as v is not near enough to c for realtivity to take effect. Is this right? I didn't use taylor expansion, so have I gone wrong somewhere. Thanks a lot. xxx
 
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goldilocks said:
So there is no contraction as v is not near enough to c for realtivity to take effect. Is this right?
No. Since the speed is small compared to c, the effect will be small. But you can still calculate it.

I didn't use taylor expansion, so have I gone wrong somewhere.
Hint: Look up the Taylor expansion of \sqrt{1 + x}, where x << 1.
 

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