Lennard-Jones potential graph w/ attractive/repulsive force

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 6K views
destroyer130
Messages
18
Reaction score
0
Capture.PNG


Based on this and the equation F = -d[itex]\Phi[/itex]/dr. I can't visualize what is positive and negative force direction (what is positive direction). So is that just mean whenever the force between 2 molecules (+), it's repulsive; and whenever it's (-), it's attractive? Thanks for checking this out.
 
Engineering news on Phys.org
destroyer130 said:
View attachment 54775

Based on this and the equation F = -d[itex]\Phi[/itex]/dr. I can't visualize what is positive and negative force direction (what is positive direction). So is that just mean whenever the force between 2 molecules (+), it's repulsive; and whenever it's (-), it's attractive? Thanks for checking this out.
What this graph is telling you is that, if the two molecules are farther apart than rm, the force between them is attractive, but if they are closer together than this, the force is repulsive.
 
What Chestermiller said.

I just want to point out that with the equation you posted the force is attractive when it is positive and repulsive when negative (not the other way around) (When the slope of the potential curve is negative the force is positive)