- #1
missmia
[SOLVED] Lenses - Thin-Lens Equation and Magnification Equation
I can't figure out what I am doing wrong, your help would be greatly appreciated :)
Here is the Homework Problem
A camera is supplied with two interchangeable lenses, whose focal lengths are 35.0 and 150.0 mm. A woman whose height is 1.80 m stands 9.00 m in front of the camera. What is the height (including sign) of her image on the film, as produced by each of the following.
(a) the 35.0 mm lens
(b) the 150.0 mm lens
ATTEMPTED SOLUTION:
\frac{1}{d_{i}} = \frac{1}{.0035m} - \frac{1}{9.0m}
which gives d_{i} = .003501m
then, I used the magnification equation: m = - \left[\frac{.003501m}{9.0m}\right] = -3.89 x 10^{-4}x
then, I used h_{i} = mh_{o} = -3.89 x 10^{-4} x 1.80m = -7.00 x 10^{-4}
But, the answer that I got is incorrect! Please Help! Thank you!
I can't figure out what I am doing wrong, your help would be greatly appreciated :)
Here is the Homework Problem
A camera is supplied with two interchangeable lenses, whose focal lengths are 35.0 and 150.0 mm. A woman whose height is 1.80 m stands 9.00 m in front of the camera. What is the height (including sign) of her image on the film, as produced by each of the following.
(a) the 35.0 mm lens
(b) the 150.0 mm lens
ATTEMPTED SOLUTION:
\frac{1}{d_{i}} = \frac{1}{.0035m} - \frac{1}{9.0m}
which gives d_{i} = .003501m
then, I used the magnification equation: m = - \left[\frac{.003501m}{9.0m}\right] = -3.89 x 10^{-4}x
then, I used h_{i} = mh_{o} = -3.89 x 10^{-4} x 1.80m = -7.00 x 10^{-4}
But, the answer that I got is incorrect! Please Help! Thank you!