Distance Between Lenses for a Magnification of 10

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SUMMARY

The problem involves calculating the distance between a convex lens and a concave lens, both with a focal length of 6 cm, to achieve a magnification of 10 for an object placed 5 cm from the convex lens. Using the lens formula 1/f = 1/u + 1/v and the magnification formula magnification = v/u, the image distance (v) for the convex lens is determined to be -30 cm. The image produced by the convex lens serves as the object for the concave lens, which must also be analyzed to find the distance between the two lenses.

PREREQUISITES
  • Understanding of lens formulas: 1/f = 1/u + 1/v
  • Knowledge of magnification calculations: magnification = v/u
  • Familiarity with convex and concave lens properties
  • Ability to sketch ray diagrams for lenses
NEXT STEPS
  • Study the derivation and application of the lens formula in optics
  • Learn how to construct ray diagrams for both convex and concave lenses
  • Explore the concept of combined lens systems and their magnification
  • Investigate practical applications of lenses in optical instruments
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding lens systems and magnification principles.

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Homework Statement



A convex lens and a concave lens both of 6cm focal length are placed to give an object which is 5cm from the convex lens of magnification of 10. How far are the lenses apart?

Homework Equations



1/f = 1/u + 1/v
Magnification=v/u


The Attempt at a Solution



Lens One: Convex

f=6cm
u=5cm
v=?

1/f = 1/u + 1/v
1/6 = 1/5 + 1/v
V=-30

Lens Two: Concave

f=-6 (concave)
To get a magnification of 10:
10 = v/u





That's all I have. I have no idea how to work out the distance between the two lenses. Can anyone help please?
 
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You also have
magnification = V/U = 30/5 = 6. So the image of the first, convex lens is 6 times as large as the object.

It really helps to sketch the lenses and draw 2 or 3 rays to determine the location and size of the image. You will see what is going on if you do this.

The image of the first lens is the object for the second.
1/f = 1/u + 1/v magnification = v/u
You know f and can use the second equation to get v as a number times u. You should be able to solve these two to get a number for u. With that, you can add the second lens to your sketch and figure out the distance between the two lenses. Good luck!
 

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