L'Hopital's Rule case: How does x^(-4/3) equal 0 when x approches infinity?

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As x approaches infinity, the expression x^(-4/3) approaches 0 because it represents the inverse of x^(4/3), which grows without bound. L'Hopital's Rule can be applied to confirm this behavior, as it shows that the limit of x^(-4/3) is indeed 0. The reasoning relies on understanding that as the denominator increases, the overall value of the fraction decreases towards zero. Therefore, the limit of x^(-4/3) as x approaches infinity is 0. This illustrates a fundamental concept in calculus regarding limits and behavior of functions at infinity.
Mohmmad Maaitah
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Homework Statement
How is this 0/0 so we can use L'Hopital's Rule?
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L'Hopital's Rule
I'm talking about the x^(-4/3) how does it equal 0 when x approch infinite??
so I can use

L'Hopital's Rule​

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$$x^{\frac{4}{3}}\rightarrow +\infty$$
so its inverse
$$x^{-\frac{4}{3}}\rightarrow +0$$
 
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