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Evaluate the following limit: lim(as x tends to 1) of [(x-1)^3]/(logx)

I tried using L'hopital's Rule, so i differentiated the top and bottom of the eqn and i got 3x(x-1)^2, then as x tends to 1 this would tend to 0.

I don't think this is correct though, and was wondering if anyone could give me some guide lines to maybe another rule to use to find the limit.

Thanks.