Lift a weight up with an EM switch

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SUMMARY

The discussion focuses on calculating the power required to lift a 30 kg weight using an electromagnetic coil. To determine the power in Watts, one must consider the force of gravity acting on the weight, which is approximately 294.3 Newtons (30 kg x 9.81 m/s²), and the height of 1 meter. The power can be calculated using the formula: Power (Watts) = Force (Newtons) x Height (meters) / Time (seconds). The specifics of the coil design and geometry also play a crucial role in the overall efficiency and effectiveness of the lifting mechanism.

PREREQUISITES
  • Understanding of basic physics principles, particularly force and power calculations.
  • Familiarity with electromagnetic coils and their operational characteristics.
  • Knowledge of gravitational force and its impact on weight.
  • Basic understanding of electrical engineering concepts related to power supply.
NEXT STEPS
  • Research the design and specifications of electromagnetic coils for lifting applications.
  • Learn about the efficiency of different coil geometries in electromagnetic lifting.
  • Explore power supply requirements for electromagnetic systems.
  • Investigate safety measures and best practices for working with electromagnetic lifting devices.
USEFUL FOR

Engineers, physicists, and hobbyists interested in electromagnetic systems, particularly those focused on lifting mechanisms and power calculations in electrical engineering applications.

The_Thinker
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Hello,

My question is simple. Let's suppose you have an electromagnetic coil with a magnetic weight in the center of it. This coil is energized, and the weight is lifted up vertically.

Now, my weight is 30 kgs. I want to lift it to a height of 1 meter. How do I calculate how much power is required to do this? How do I calculate it in terms of Watts?

For the mods: This is not a homework question. I am trying to understand something.
 
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There is no easy relation for this, it depends on your coil, the weight, and the overall geometry.
 

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