Lift and screw impact velocity

In summary: Yes, because it is only reference frame and displacement problem. If you consider that lift and screw in your Initial position where screw velocity and lift velocity are same I mean vo=0; but displacement of floor x=0 and displacement of screw =3m. displacement changes due to velocity for screw and floor.However, screw is falling when lift is accelerating. They are impacting when the displacement of floor is 11.41m but displacement of screw is 8.41m. It is really hard to understand what is happening there.
  • #1
robax25
238
3

Homework Statement


Consider the elevator and screw in Example 2-17. Assume the velocity of
the elevator is 16 mls upward when the screw separates from the ceiling.
(a) How far does the elevator rise while the screw is falling? How far does
the screw fall? . I have only problem second part of the question. Lift height 3m.

Homework Equations


t=0.659s a (lift)=4m/s²,g(screw)=9.81m/s²
x=Vot+0.5at²

The Attempt at a Solution


X lift=11.41m
 

Attachments

  • Unbenannt.png
    Unbenannt.png
    42.6 KB · Views: 398
  • Unbenannt1.png
    Unbenannt1.png
    38.5 KB · Views: 429
Last edited:
Physics news on Phys.org
  • #2
You don't state the internal height of the lift cage.
I see no attempt at the second part.
 
  • #3
robax25 said:

Homework Statement


Consider the elevator and screw in Example 2-17. Assume the velocity of
the elevator is 16 mls upward when the screw separates from the ceiling.
(a) How far does the elevator rise while the screw is falling? How far does
the screw fall? . I have only problem second part of the question.

Homework Equations


t=0.659s a (lift)=4m/s²,g(screw)=9.81m/s²
x=Vot+0.5at²

The Attempt at a Solution


X lift=11.41m
Is there a figure that is supposed to go with this question (or Example 2-17)? Can you use the Upload button to attach it please?
 
  • #4
I am done almost.However, I have a little bit confusion. It is relative velocity question. If I consider that displacement of screw and lift differently and I find displacement of the screw -2.13m and I do deduction between initial height due to velocity and I get right answer. Book is right in one sense if I consider that the total displacement of the lift 11.41 and I just do deduction from the height of lift. I get the answer. My question why do I not consider them separately?
 
  • #5
robax25 said:
I am done almost.However, I have a little bit confusion. It is relative velocity question. If I consider that displacement of screw and lift differently and I find displacement of the screw -2.13m and I do deduction between initial height due to velocity and I get right answer. Book is right in one sense if I consider that the total displacement of the lift 11.41 and I just do deduction from the height of lift. I get the answer. My question why do I not consider them separately?
Please state the whole problem and show all your working.
 
  • #6
Actually I have solved the problem using sketch.
 
  • #7
robax25 said:
Actually I have solved the problem using sketch.
Does that mean you are no longer confused?
 
  • #8
yes, because it is only reference frame and displacement problem. If you consider that lift and screw in your Initial position where screw velocity and lift velocity are same I mean vo=0; but displacement of floor x=0 and displacement of screw =3m. displacement changes due to velocity for screw and floor.However, screw is falling when lift is accelerating. They are impacting when the displacement of floor is 11.41m but displacement of screw is 8.41m. It is really hard to understand what is happening there.
 
  • #9
robax25 said:
yes, because it is only reference frame and displacement problem. If you consider that lift and screw in your Initial position where screw velocity and lift velocity are same I mean vo=0; but displacement of floor x=0 and displacement of screw =3m. displacement changes due to velocity for screw and floor.However, screw is falling when lift is accelerating. They are impacting when the displacement of floor is 11.41m but displacement of screw is 8.41m. It is really hard to understand what is happening there.
You have to decide whether your reference frame continues up at the initial velocity of the lift or accelerates with the lift.
If the latter then you have to introduce a virtual force to account for the fact that the lift is not accelerating (in this frame) despite the imbalanced forces on it.
 
  • #10
If my reference frame Initial position of the lift, then, it is really easy to solve.I mean floor and also Initial Postion of the screw which is located 3m high from the floor.Your position is changing due to velocity and acceleration. Floor and screw have same velocity once and screw is falling down when the lift is accelerating. It happens also in real life. I mean when you feel jark, or sudden change of motion, you feel negative force. That's way we are going foward and backward when we are standing on a bus.
 
  • #11
robax25 said:
I mean when you feel jark, or sudden change of motion, you feel negative force.
"Change of motion" is a bit vague. Jerk is the rate of change of acceleration. When a bus comes to a stop, the acceleration suddenly changes from small, negative, to zero. This abruptly changes your force balance, and is why you tend to fall over if standing and bracing yourself against the negative acceleration.

I'm still unclear whether you have a remaining issue. I asked if you were no longer confused. You replied "yes" but finished with
robax25 said:
It is really hard to understand what is happening there.

If I interpret your answers correctly, you are confident working with the initial position of the lift as the reference frame and get the right answer. In what frame, if any, are you confused? Initial velocity of lift? Acceleration of lift?
 
  • #12
You are right and understand my Situation. In university exam, they give very hard and tough question. I am currently studying mechanical Engineering in Germany. Most of the question, they ask very difficult. It sometimes happens that I can not even imagine what they ask such kind of non-sense question.There is no limitation asking question. you can only pass if you understand the real phenomena of the problem. that's why I am finishing my word using the sentence.
 

1. What is lift and screw impact velocity?

Lift and screw impact velocity is the speed at which a screw or helical structure moves through a fluid or solid medium, creating lift or thrust in the process. It is a crucial factor in understanding the movement and efficiency of objects such as propellers, turbines, and screws.

2. How is lift and screw impact velocity calculated?

Lift and screw impact velocity is calculated by taking into account the pitch (distance between the screw's threads) and rotational speed of the screw, as well as the density and viscosity of the medium it is moving through. The formula for calculating lift and screw impact velocity is v = pω, where v is velocity, p is pitch, and ω is rotational speed.

3. What is the relationship between lift and screw impact velocity and lift force?

The lift force generated by a screw or helical structure is directly proportional to its impact velocity. This means that the faster the screw moves through the medium, the greater the lift force it will generate. However, there are other factors such as the angle of attack and shape of the screw that also affect lift force.

4. How does the viscosity of the medium affect lift and screw impact velocity?

The viscosity of the medium has a significant impact on the efficiency and performance of lift and screw mechanisms. A higher viscosity means that the medium is thicker and more resistant to movement, resulting in a lower impact velocity and less lift force. On the other hand, a lower viscosity allows for higher impact velocities and greater lift forces.

5. In what applications is understanding lift and screw impact velocity important?

Lift and screw impact velocity is important in a wide range of fields and applications, including aerodynamics, hydrodynamics, and fluid mechanics. It is also crucial in the design and operation of various machines and devices, such as aircraft, boats, and pumps. Additionally, understanding lift and screw impact velocity is essential for optimizing energy efficiency and reducing drag in these applications.

Similar threads

  • Introductory Physics Homework Help
Replies
17
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
3K
  • Introductory Physics Homework Help
2
Replies
35
Views
4K
  • Introductory Physics Homework Help
2
Replies
38
Views
1K
  • Introductory Physics Homework Help
Replies
18
Views
2K
  • Introductory Physics Homework Help
Replies
18
Views
7K
  • Introductory Physics Homework Help
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
6K
Back
Top