Lifting height of a box in a truck going over a speed bump

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SUMMARY

The discussion centers on calculating the lifting height of a 50 kg package in a truck traveling at 60 km/h over a speed bump. The height to which the package rises is influenced by the dimensions of the speed bump and the truck's suspension system, which affects energy transfer. Participants emphasize that not all speed bumps yield the same reaction and suggest that an upper bound for the lifting height can be calculated based on the truck's kinetic energy and suspension characteristics. The conversation highlights the importance of understanding the physics involved in such scenarios.

PREREQUISITES
  • Understanding of basic physics principles, particularly kinetic energy (KE)
  • Familiarity with truck suspension systems and their impact on load dynamics
  • Knowledge of speed bump dimensions and their effects on vehicle motion
  • Ability to analyze vertical launch velocity components in physics
NEXT STEPS
  • Research the mechanics of truck suspension systems and their role in load stability
  • Learn about calculating kinetic energy and its implications for moving vehicles
  • Explore the physics of projectile motion to understand vertical launch velocities
  • Investigate different types of speed bumps and their design specifications
USEFUL FOR

Engineers, physics students, logistics professionals, and anyone involved in vehicle dynamics or load management will benefit from this discussion.

jamesdhurai
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Homework Statement
how to find lifting height
Relevant Equations
Any
hey guys need to know the way to find the solution to the problem.

Consider a truck which is traveled in a speed of 60km per hour.

A package weighs 50 kg is placed inside the truck with side supports to arrest the movement in x and y direction. But the top movement (z axis) is not arrested.

In this case, if the car moves over a speed breaker, how high the package will lift from its position?
 
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Welcome to the PF. :smile:
jamesdhurai said:
Homework Statement:: how to find lifting height
Relevant Equations:: Any

hey guys need to know the way to find the solution to the problem.

Consider a truck which is traveled in a speed of 60km per hour.

A package weighs 50 kg is placed inside the truck with side supports to arrest the movement in x and y direction. But the top movement (z axis) is not arrested.

In this case, if the car moves over a speed breaker, how high the package will lift from its position?
We require you to show your own work on schoolwork problems before we can offer tutorial help. That said, as @Lnewqban points out, the height that the box will rise to depends on the height and shape of the speedbump, and the suspension of the truck. You must have been given more information in this problem, no?
 
Lnewqban said:
That height depends on the dimensions of the speed bump and on the capability of the truck's suspension to reduce the energy transferred to the package.

Not all speed bumps produce the same reaction.
Please, see:
https://en.wikipedia.org/wiki/Speed_bump#Comparison_to_speed_bumps

:cool:
Sure, but it is possible to calculate an upper bound.
 
Welcome, James :cool:
Sorry, I did not see it was your first post.
Could you show us the whole wording of the problem and your work so far?
 
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haruspex said:
Sure, but it is possible to calculate an upper bound.

"the distance between front bumper and the box" isn't really a calculation, more of an observation, from a safe distance.

(abject apologies to the OP if that's actually the textbook answer)
 
hmmm27 said:
"the distance between front bumper and the box" isn't really a calculation, more of an observation, from a safe distance.

(abject apologies to the OP if that's actually the textbook answer)
I was not referring to that (is that from the link you posted?). It is possible to calculate an upper bound from the info in the question.
 
I didn't post a link (that I recall): just one of the many vague uses for "" to indicate personal distancing from a saying.

I don't see how you could calculate an upper bound, given the incredible breadth of stick-figure physics.

(and I'd like to change my answer : using the front bumper to stop the rotation, the box could be flung into outer space, given enough ridiculous parameters for the "truck" and "speedbump")
 
hmmm27 said:
using the front bumper to stop the rotation, the box could be flung into outer space, given enough ridiculous parameters for the "truck" and "speedbump")
What vaguely reasonable mechanism would cause the box to rise faster than the max upward speed of the bed it rests on?
 
  • #10
haruspex said:
What vaguely reasonable mechanism would cause the box to rise faster than the max upward speed of the bed it rests on?
None that I can think of, offhand. Would you expect it to ?
 
  • #11
hmmm27 said:
None that I can think of, offhand. Would you expect it to ?
No, which is why the jolt would not propel the box to a greater height than it could, in principle, raise the truck to. And that is limited by the KE of the truck.

In practice, the box does reach a greater height than the truck does because of the truck's suspension. But that is because the upward movement of the top of the truck is slowed as the suspension reaches relaxed position and the portion of mass below the suspension holds it back. Meanwhile, the box rises a little further under its acquired KE.
 
  • #12
haruspex said:
No, which is why the jolt would not propel the box to a greater height than it could, in principle, raise the truck to. And that is limited by the KE of the truck.
We seem to be talking at cross-purposes. Your question was concerning velocity, not height.
 
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  • #13
hmmm27 said:
We seem to be talking at cross-purposes. Your question was concerning velocity, not height.
The height the box reaches is determined by the vertical component of its launch velocity.
 

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