Light after a Polarizer Question

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SUMMARY

The discussion centers on calculating the angle between two polarizers to achieve a specific transmitted intensity of light. Given an initial intensity of 240 W/m², the goal is to find the angle that results in a transmitted intensity of 37.5% after passing through both polarizers. The calculations confirm that the angle should be 30 degrees, derived from the equation I=I0cos²θ, where I1 is halved after the first polarizer and I2 is 0.375I1 after the second. The solution is validated by the forum participants.

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Homework Statement


Initially unpolarized light with an intensity of 240W/m2 is incident on a series of two polarizers. What should be the angle between to the axes of the two polarizers such that the transmitted intensity after the second polarizer is 37.5% of the incident one?


Homework Equations



I=I0cos2[tex]\theta[/tex]



The Attempt at a Solution



I1=.5Iocos2[tex]\theta[/tex] (unpolarized light is reduced by halve after the first polarizer)
this can also be written at 2I1=Io

We are given that I2=0.375I1
2I1=Io so I2 really equals 0.75I1

0.75I1 = I1cos2[tex]\theta[/tex]
0.75=cos2[tex]\theta[/tex]
[tex]\theta[/tex] = 30 degrees

Did I do this correctly?
Thanks for all your help...
 
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