Light intensity of a flashlight?

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SUMMARY

The discussion focuses on calculating the intensity of light from a flashlight as it hits a wall at a distance L from the bulb, given a wattage W and a cone angle theta. The intensity is derived using the formula I = W/(π*(L*tan(theta))^2), where the area of the cone's base is a circle. Additionally, the energy absorbed by the wall over a time Δt is calculated as Energy = W*Δt, confirming that the wall absorbs all emitted light. The participants emphasize the relationship between cone angle and intensity, noting that intensity increases as theta approaches 0 and decreases as theta approaches π/2.

PREREQUISITES
  • Understanding of light intensity and its mathematical representation
  • Familiarity with geometric concepts, particularly the area of a circle
  • Knowledge of basic physics principles, specifically power and energy
  • Ability to manipulate trigonometric functions, such as tangent
NEXT STEPS
  • Study the derivation of the area of a circle and its application in physics
  • Learn about the relationship between light intensity and distance in conical beams
  • Explore the implications of varying angles on light distribution
  • Investigate the concept of energy absorption in different materials and surfaces
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Students in physics, particularly those studying optics and energy transfer, as well as educators looking for practical examples of light intensity calculations.

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Homework Statement


A flashlight lights up a wall a distance L from the small bulb whose wattage is given by W. The conical beam emerges from the flashlight at an angle theta. What is the intensity of light as it hits the wall a distance L from the bulb?


Homework Equations


I = Power/Area


The Attempt at a Solution


I = W/[area of cone] = W/(pi*Lcos(theta))

I'm having a bit of trouble understanding this problem! Please help!
Thank you!
 
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The problem is basically asking hte amount of energy incident on the wall at the end of a light cone. The cone's base is the area that the light is incident upon. Now if you have a set distance L for the "height" of the cone, you can determine the radius of the base of that cone using the angle given. The base is a simple circle. Then you can use your intensity = power/area formula. By the way, your equation for the area of the cone is incorrect. Look at the dimensions, it also might help to draw a diagram for it.
 
Thank you!
so basically it would be
Intensity = power/area of circle?
Therefore, I = W/(pi*(Ltan(theta))^2)??
 
Yup! Notice how as theta -> 0, the intensity blows up as expected if you make that cone smaller and smaller and smaller. Also as theta -> pi/2, the cone expands to being infinitely big so the intensity, that is power per area, drops to 0.
 
Also,
there was another part to this question I had trouble understanding

Question
How much energy is absorbed by the wall in a time Δt?

attempt
Energy absorbed = Power * Δt
= [W/(pi*(Ltan(theta))^2)] * Δt
 
Assuming the wall absorbs all the light, it's simply Power * Time. Remember, a watt is a joule per second.
 
Oh, I see.
Therefore, the answer would JUST be
W*Δt
 
OH!
I get it.
What I was trying to do was
Energy absorbed = Intensity * area of the absorbed energy * Δt
But in this case, the entire wall is the area of the absorbed energy therefore the area part in the Intensity would cancel out thus simply giving me W*Δt
Is that correct?
 
Yup!
 
  • #10
Thank you SO much!
 

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