Light is Reflecting-EASYYYY PROBLEM but help needed.

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Homework Help Overview

The discussion revolves around a problem involving the reflection of light from two perpendicular surfaces, where participants are tasked with finding the angle between the incoming ray and the outgoing ray. The context is rooted in optics, specifically the principles of reflection.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the relationship between angles formed by the incoming and outgoing rays, questioning how to determine these angles without given values. Some suggest labeling angles and using properties of complementary angles in triangles.

Discussion Status

The discussion is active, with participants providing insights and questioning each other's understanding of the problem setup. There is a focus on clarifying the relationships between the angles involved, though no consensus has been reached regarding the specific values or final conclusions.

Contextual Notes

Some participants note the lack of specific angle values provided in the problem, which complicates the determination of the angles between the rays. The discussion also reflects on the definitions of angles in relation to the normal and horizontal surfaces.

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[SOLVED] Light is Reflecting-EASYYYY PROBLEM! but help needed.

Homework Statement



Figure 33-47 shows light reflecting from two perpendicular reflecting surfaces A and B. Find the angle between the incoming ray i and the outgoing ray r'.
The figure is attached to this thread!

Homework Equations



angle of incedence = angle of reflection

The Attempt at a Solution



don't know where to start from
 

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The two acute angles in a right triangle sum to 90 degrees. They are complementary. Use that.
 
oooo well thank you Dick, but how in the world can you find out those two angles, if no other values of angles are given. like i no the normal line equals to 90 degrees also, but how can you find the angles.
 
The angle between the incoming and the outgoing ray is the difference between the angle theta in your picture and the angle r' makes with the horizontal surface B (call it phi). Start labelling all of the angles you can find as either theta or 90-theta. You should be able to show phi=theta.
 
and congratulations Dick on receiving the 2007 PF Award!
 
physicsbhelp said:
so the "angle between the incoming and the outgoing ray" can be labeled like beta so basically beta=theda-phi?

Thanks for the congrats. Yes, theta and phi are the angles the incoming and outgoing make with a horizontal line. If those are equal, they are parallel.
 
whoA! wait a second. i thought tha theda made an angle with the vertical line and normal line. like in the diagram= that shows what theda is.
 
'the diagram' that I'm looking at shows theta as the angle between the incoming ray and the normal to the vertical reflector - which is horizontal.
 
You are asked for the angle BETWEEN incoming and outgoing. If they are parallel, the angle between them is zero.
 
  • #10
I think you just don't understand the question. You can't determine any of the angles in the problem. You aren't given any. All you can say is what the relation is between the angles. If you understand that the incoming and outgoing ray are parallel, then you are DONE. They make the same angle with the horizontal. The angle between them is ZERO. Write that answer down along with why you believe it and turn it in.
 

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