Light ray passing thru plastic block

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SUMMARY

The discussion centers on calculating the index of refraction of a transparent plastic block when a light ray enters at an angle of incidence of θ1 = 77.7°. The relevant equations include Snell's Law (n1sin(θ1)=n2sin(θ2)) and the critical angle formula (sin(θcrit)=n2/n1). The user attempted to derive n2 using these equations but encountered inconsistencies, particularly with the angle notation. The correct approach involves ensuring distinct symbols for angles and accurately applying Snell's Law to find the refractive index.

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Homework Statement



A light ray passes downward into a block of transparent plastic with an angle of incidence of θ1 = 77.7°.

If total internal reflection is to occur when the light strikes the left edge of the block at interface B, what is the index of refraction of the plastic?

Homework Equations



Snell's Law - n1sin(θ1)=n2sin(θ2)

sin(θcrit)=n2/n1

The Attempt at a Solution



I thought that I could use the law of refraction at interface A and the equation for the critical value at interface B (since total internal refraction occurs there), and use those two equations to solve for n2. I've done all manners of substitutions, but nothing that yields a reasonable answer.

I would really appreciate a nudge in the right direction.

Thanks in advance!
 

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Hello.
Your outline of how to approach the problem sounds good. Can you show your work so we can see what you've done?
 
I solved Snell's law for sin(θ2) which yielded n1sin(θ1)/n2.

I set that equal to n2/n1. Then I solved for n2 which gave me n2=+-n1√sin(θ1).

When I solve I get some value like .98755 which is less than one making it obviously incorrect.
 
I think you're using the same symbol θ2 for two different angles.
 

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