Liminf to limsup transformation question

  • Thread starter Thread starter transgalactic
  • Start date Start date
  • Tags Tags
    Transformation
Click For Summary
SUMMARY

The discussion centers on the mathematical transformation of sequences, specifically the relationship between the limit inferior (liminf) and limit superior (limsup) when a bounded sequence is multiplied by -1. It is established that liminf(-y_n) equals -limsup(y_n) as n approaches infinity. An example is provided with the sequence 1/2, 0, 2/3, 0, 3/4, which has a liminf of 0 and a limsup of 1. Upon multiplying by -1, the transformed sequence yields a liminf of -1 and a limsup of 0, demonstrating the reversal of limits through multiplication by a negative scalar.

PREREQUISITES
  • Understanding of bounded sequences in real analysis
  • Familiarity with the concepts of limit inferior and limit superior
  • Knowledge of subsequences and their convergence properties
  • Basic proficiency in mathematical notation and sequence manipulation
NEXT STEPS
  • Study the properties of bounded sequences in real analysis
  • Learn about the proofs of liminf and limsup relationships
  • Explore subsequence convergence and its implications in analysis
  • Investigate the effects of scalar multiplication on sequences
USEFUL FOR

Mathematicians, students of real analysis, and anyone interested in the properties of sequences and their transformations in mathematical contexts.

transgalactic
Messages
1,386
Reaction score
0
y_n is a bounded sequence

liminf(-y_n)=-limsup(y_n)
n->infinity

i can't understand how it happens??
 
Physics news on Phys.org
Multiply as sequence of number reverses the direction. If, for example, the sequence were increasing, say 1, 2, 3, 4, etc., then multiplying by -1 changes it to -1, -2, -3, -4, etc. which is decreasing.

The sequence 1/2, 0, 2/3, 0, 3/4, ..., does not converge but has one subsequence, 0, 0, 0, 0,..., that converges to 0 and another, 1/2, 2/3, 3/4, ..., that converges to 1. For this sequence liminf= 0 and limsup= 1. Multiplying each term by -1 gives -1/2, 0, -2/3, 0, -3/4, ... which has one sequence, 0, 0, 0, ..., that converges to 0 and another, -1/2, -2/3, -3/4, ..., that converges to -1. For this sequence, liminf= -1 and limsup= 0.
 
thanks
 

Similar threads

Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
13
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
11
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
8
Views
3K