Limit Calculator for \sqrt{x^{2}+5} and \sqrt{x^{2}+2} with x\rightarrow \infty

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Homework Statement


Calculate the limit of
[tex] \lim_{x\rightarrow \infty} \frac{\sqrt{x^{2}+5} - x}{\sqrt{x^{2}+2} - x}[/tex]

Homework Equations


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The Attempt at a Solution


Neither multiplying with the conjugate nor trying to break out x helps me, as I'm left with "0/0" in those cases.
 
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While I do know l'hospital's rule, we have not yet covered it in the course. The problem should be solved without using (sadly).
 


walker242 said:

Homework Statement


Calculate the limit of
[tex] \lim_{x\rightarrow \infty} \frac{\sqrt{x^{2}+5} - x}{\sqrt{x^{2}+2} - x}[/tex]

how about this, multiply by both conjugates of the numerator & denominator to get:

[tex] \lim_{x\rightarrow \infty} \frac{5 \sqrt{x^{2}+2} + x}{2 \sqrt{x^{2}+5} +x}[/tex]

already looking in better shape, as its not a difference term that is leading to the zero, which ws the tricky bit, so from here I'd try multiplying through by:

[tex] \lim_{x\rightarrow \infty} \frac{\frac{1}{x}}{\frac{1}{x}}[/tex]

this should change the terms containing x in the numerator & denominator from tending to infinity, to ones tending to zero...
 


lanedance said:
how about this, multiply by both conjugates of the numerator & denominator to get:

[tex] \lim_{x\rightarrow \infty} \frac{5 \sqrt{x^{2}+2} + x}{2 \sqrt{x^{2}+5} +x}[/tex]

already looking in better shape, as its not a difference term that is leading to the zero, which ws the tricky bit, so from here I'd try multiplying through by:

[tex] \lim_{x\rightarrow \infty} \frac{\frac{1}{x}}{\frac{1}{x}}[/tex]

this should change the terms containing x in the numerator & denominator from tending to infinity, to ones tending to zero...

[tex]\lim_{x\rightarrow \infty} \frac{5\sqrt{x^{2}+2} + x}{2\sqrt{x^{2}+5} +x} = \lim_{x\rightarrow\infty} = \frac{5}{2}\frac{x(\sqrt{1+\frac{2}{x}})+1}{x(\sqrt{1+\frac{5}{x}})+1} = \frac{5}{2}\cdot\frac{2}{2} = \frac{5}{2}<br /> [/tex]

Cheers!
 


walker242 said:
[tex]\lim_{x\rightarrow \infty} \frac{5\sqrt{x^{2}+2} + x}{2\sqrt{x^{2}+5} +x} =[/tex]


[tex]\lim_{x\rightarrow\infty}\frac{5}{2}\cdot \lim_{x\rightarrow\infty}\frac{x\bigg( \sqrt{1+ \frac{2}{x^2}} + 1\bigg)}{x\bigg(\sqrt{1 + \frac{5}{x^2}}+1\bigg)} =[/tex]


[tex]\frac{5}{2}\cdot\frac{2}{2} = \frac{5}{2}[/tex]

There were some significant errors in this (highlighted in the

quote box) post from a user, that I felt one of the corrected

versions should be shown.