Limit Calculator for \sqrt{x^{2}+5} and \sqrt{x^{2}+2} with x\rightarrow \infty

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Homework Help Overview

The discussion revolves around calculating the limit of the expression \(\lim_{x\rightarrow \infty} \frac{\sqrt{x^{2}+5} - x}{\sqrt{x^{2}+2} - x}\). The subject area pertains to limits in calculus, specifically focusing on indeterminate forms as \(x\) approaches infinity.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to simplify the limit expression but encounters a "0/0" indeterminate form. Some participants suggest using L'Hôpital's rule, while others note that it has not been covered in the course. There are discussions about multiplying by conjugates to resolve the indeterminate form, with one participant proposing a specific manipulation of the expression.

Discussion Status

The discussion is ongoing, with participants exploring various algebraic manipulations to address the limit. There is no explicit consensus on a final approach, but some guidance has been offered regarding the use of conjugates and the transformation of terms as \(x\) approaches infinity.

Contextual Notes

Participants are constrained by the course material, which does not include L'Hôpital's rule, and there are indications of previous errors in the reasoning that have been highlighted for correction.

walker242
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Homework Statement


Calculate the limit of
<br /> \lim_{x\rightarrow \infty} \frac{\sqrt{x^{2}+5} - x}{\sqrt{x^{2}+2} - x}<br />

Homework Equations


-

The Attempt at a Solution


Neither multiplying with the conjugate nor trying to break out x helps me, as I'm left with "0/0" in those cases.
 
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do you know l'hospital's rule? could help here i think
 


While I do know l'hospital's rule, we have not yet covered it in the course. The problem should be solved without using (sadly).
 


walker242 said:

Homework Statement


Calculate the limit of
<br /> \lim_{x\rightarrow \infty} \frac{\sqrt{x^{2}+5} - x}{\sqrt{x^{2}+2} - x}<br />

how about this, multiply by both conjugates of the numerator & denominator to get:

<br /> \lim_{x\rightarrow \infty} \frac{5 \sqrt{x^{2}+2} + x}{2 \sqrt{x^{2}+5} +x}<br />

already looking in better shape, as its not a difference term that is leading to the zero, which ws the tricky bit, so from here I'd try multiplying through by:

<br /> \lim_{x\rightarrow \infty} \frac{\frac{1}{x}}{\frac{1}{x}}<br />

this should change the terms containing x in the numerator & denominator from tending to infinity, to ones tending to zero...
 


lanedance said:
how about this, multiply by both conjugates of the numerator & denominator to get:

<br /> \lim_{x\rightarrow \infty} \frac{5 \sqrt{x^{2}+2} + x}{2 \sqrt{x^{2}+5} +x}<br />

already looking in better shape, as its not a difference term that is leading to the zero, which ws the tricky bit, so from here I'd try multiplying through by:

<br /> \lim_{x\rightarrow \infty} \frac{\frac{1}{x}}{\frac{1}{x}}<br />

this should change the terms containing x in the numerator & denominator from tending to infinity, to ones tending to zero...

\lim_{x\rightarrow \infty} \frac{5\sqrt{x^{2}+2} + x}{2\sqrt{x^{2}+5} +x} = \lim_{x\rightarrow\infty} = \frac{5}{2}\frac{x(\sqrt{1+\frac{2}{x}})+1}{x(\sqrt{1+\frac{5}{x}})+1} = \frac{5}{2}\cdot\frac{2}{2} = \frac{5}{2}<br /> <br />

Cheers!
 


walker242 said:
\lim_{x\rightarrow \infty} \frac{5\sqrt{x^{2}+2} + x}{2\sqrt{x^{2}+5} +x} =


\lim_{x\rightarrow\infty}\frac{5}{2}\cdot \lim_{x\rightarrow\infty}\frac{x\bigg( \sqrt{1+ \frac{2}{x^2}} + 1\bigg)}{x\bigg(\sqrt{1 + \frac{5}{x^2}}+1\bigg)} =


\frac{5}{2}\cdot\frac{2}{2} = \frac{5}{2}

There were some significant errors in this (highlighted in the

quote box) post from a user, that I felt one of the corrected

versions should be shown.
 


This thread is 2 years old. You've been here long enough to know not to necropost.
 

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