# Limit comparisons (reviewing my Calc 1)

1. Dec 16, 2007

### rocomath

So recently I been reviewing my graphing along with my Calculus 1.

I'm currently reading this problem and I was thinking, why not just compare it to a graph that I already know.

$$\lim_{x \rightarrow 5^{+}}\frac{6}{x-5}$$

with comparison to whose limit also goes to Infinity as it approaches from the right.

$$\lim_{x \rightarrow 0^{+}}\frac{1}{x}$$

Basically, my interpretation is that the first graph is simply stretched vertically by 6 and shifted 5 units from the graph of 1\x.

Is it ok for me to compare limits of similar functions such as the ones I just compared?

2. Dec 16, 2007

### Dick

It's ok with me. Your description of the transformation from one to the other is correct. The sense in which these functions are 'similar' is that they are related by a change of variable.