Sin(5r)/r Limit Evaluation: How to Handle 5 in the Equation

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SUMMARY

The limit evaluation of sin(5r)/r as r approaches 0 can be resolved using the substitution method. Specifically, the known limit lim as r->0 of sin(r)/r equals 1 is applicable here. By substituting 5r for r, the limit transforms to lim as r->0 of sin(5r)/(5r) multiplied by 5, resulting in a final limit of 5. This technique is essential for handling similar limits in calculus.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with the limit property lim as x->0 of sin(x)/x = 1
  • Basic substitution techniques in mathematical analysis
  • Knowledge of trigonometric functions and their behavior near zero
NEXT STEPS
  • Study advanced limit evaluation techniques in calculus
  • Learn about L'Hôpital's Rule for indeterminate forms
  • Explore Taylor series expansions for trigonometric functions
  • Investigate applications of limits in real-world scenarios
USEFUL FOR

Students and educators in mathematics, particularly those focusing on calculus, as well as anyone looking to strengthen their understanding of limit evaluation techniques.

NINHARDCOREFAN
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lim as r->0 for sin(5r)/r
I know that sinr/r=1 but with that 5r it's no use. So how do I take it into account for 5?
 
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Never mind
 
I take it you saw that substitution...Good,then.Try to remember the method,it's useful in many cases.

Daniel.
 

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