Limit of a Two-Dimensional Function with Positive Inputs: Solving for -1/5

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SUMMARY

The limit of the two-dimensional function as (x,y) approaches (0+, 0+) is calculated as follows: the numerator approaches 1 while the denominator approaches -5, resulting in a limit of -1/5. The multiple-choice options presented in the homework include A) \(\stackrel{\nearrow}{\rightarrow}\frac{1}{5}\), B) \(\frac{1}{5}\), C) \(\stackrel{\nearrow}{\rightarrow}1\), and D) 1. The notation \(\stackrel{\nearrow}{\rightarrow}\) is questioned, indicating confusion over its meaning in this context.

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Homework Statement


[itex] \lim _{ (x,y)\rightarrow (0^{ + },0^{ + }) }{ \frac { { e }^{ \sqrt { x+y } } }{ 4x+2y-5 } }[/itex]

Homework Equations


eh.

SO I did the problem. I usually sub 1/n for 0+ in most of these, but clearly the top goes to 1 from +inf, and the bottom goes to -5... Hence... -1/5

But.
The multiple choice was

A)[itex]\stackrel{\nearrow}{\rightarrow}\frac {1 }{ 5 }[/itex]

B) [itex]\frac {1 }{ 5 }[/itex]


C)[itex]\stackrel{\nearrow}{\rightarrow}1[/itex]

D) 1

What on Earth does [itex]\stackrel{\nearrow}{\rightarrow}[/itex] mean?!??
 
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Nothing wrong with what you did. I have no idea what they are trying to say.
 

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